1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Series (Partial Sums )

  1. Apr 3, 2009 #1
    1. The problem statement, all variables and given/known data

    How to find the Sn of this patial sum : 1/n+3 - 1/ n+1 ??

    2. Relevant equations

    Finding the terms

    3. The attempt at a solution
    In fact, I tried finding s1 and s2 and so on till s6 and I found that the Sn is -1/ n+2 after I canceled the terms, is that right ??
     
  2. jcsd
  3. Apr 3, 2009 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    If Sn= 1/(n+3)- 1/(n+1) then Sn+1= 1/(n+4)- 1/(n+2). Subtracting these two consecutive partial sums gives
    [tex]]\frac{1}{n+4}- \frac{1}{n+2}- \frac{1}{n+3}+ \frac{1}{n+1}[/tex]
    What does that give you?
     
  4. Apr 3, 2009 #3
    Are you trying to say that this method gives us Sn term directly, without a need for any subs. and finding terms ???
     
    Last edited: Apr 3, 2009
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Series (Partial Sums )
Loading...