Series Resistor Problem: Finding the Equivalent Resistance

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The discussion focuses on calculating the equivalent resistance of a circuit with resistors in both series and parallel configurations. Initially, the user mistakenly calculated the equivalent resistance for two resistors in series as 2R, but later recognized that the two resistors on the left are actually in parallel. After correcting the approach, the user determined the equivalent resistance for the parallel resistors to be R/2. Finally, by adding the resistance of the last resistor in series, the total equivalent resistance was correctly calculated as 3R/2. The problem illustrates the importance of correctly identifying resistor configurations in circuit analysis.
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Homework Statement



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Homework Equations





The Attempt at a Solution



What I did was I knew that the their are two resistors in series

1/req= 1/R + 1/R = 1/2R

req= 2R

Where I get confused is how do I include the other resistor since I believe that it is in series?
 
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The two resistors on the left are in parallel , that is the current splits up through the two branches before going through the last one.
 
Wow my addition was off... I figured it out, it is supposed to be 2/R and since like you said it splits up the total resistance would be req=R/2

R/2 +R = 3R/2
 
Got it.
 

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