Series Soln to a Diff Eqn: can't understand one of the steps

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kostoglotov
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Homework Statement



solve y" - 2xy' + y = 0

Homework Equations

The Attempt at a Solution



in the worked example, the book gets from

here:

[tex]\sum\limits_{n=0}^{\infty} (n+1)(n+2)c_{n+2}x^n - \sum\limits_{n=1}^{\infty}2nc_nx^n + \sum\limits_{n=0}^{\infty}c_nx^n = 0[/tex]

to here:

[tex]\sum\limits_{n=0}^{\infty} [(n+1)(n+2)c_{n+2} - (2n-1)c_n]x^n = 0[/tex]

by way of:

[tex]\sum\limits_{n=1}^{\infty}2nc_nx^n = \sum\limits_{n=0}^{\infty}2nc_nx^n[/tex]

How is this last part justified?
 
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What is the value of ##2nc_nx^n## when ##n=0##?
 
DEvens said:
What is the value of ##2nc_nx^n## when ##n=0##?

I considered that. It's zero. But assuming [itex]c_n[/itex] exists, won't [itex]2nc_nx^n \neq 0 \ for \ n=1[/itex]?
 
kostoglotov said:
I considered that. It's zero. But assuming [itex]c_n[/itex] exists, won't [itex]2nc_nx^n \neq 0 \ for \ n=1[/itex]?

Yes, but that is irrelevant. The two sums differ by the presence/absence of the ##n = 0## term, which is zero!
 
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