Series solution of first order ODE

soverylost
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Homework Statement



Find two non-zero terms of the power series solution of
y' = 1 + y^2 ,y(0) = 0
by using series substitution y(x) = sum (k=0 to inf) [a][/k] *x^k

Homework Equations



The Attempt at a Solution



First take the derivative of the power series to get
y' = sum (k=0 to inf) (k+1)*[a][/k+1]*x^k

Plug y and y' into the original ODE, here is where my problem is.
I want the powers of x to match so that i can match the coefficients of the series and get a recursive relationship to find the non-zero terms. How do i deal with the y^2 term? How do I square a series and still get matching x-terms?
 
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Remember, you are only asked to find the first couple of terms. So you just multiply out the first few terms the long way. For example, to start multiplying out these two:

a_0 + a_1x + a_2x^2 + ...
b_0 +b_1x + b_2x^2 + ...

You would get:

a_0b_0 + (a_0b_1 + a_1b_0)x + ...

and do you see how to get all the x2 terms if you need them? So do that method for multiplying the series for y by itself for as many terms as you need.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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