Setting Derivative = 0 and solving

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In summary, the conversation discusses the legality of multiplying a fraction by zero when setting the derivative equal to zero and solving for a variable. It is determined that this is acceptable, and an alternative method of dividing the left side by x/x is also mentioned.
  • #1
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Homework Statement


I'm currently working on a problem that requires me to set the derivative = 0 and solve for a variable (call it x). The derivative comes out to be a fraction, with x terms in both the numerator and denominator. Is it legal to just multiply 0 by the denominator (thereby canceling it) even if it has the term of interest as part of it?

Simple Ex: say the derivative came out to be x-3 / 2x. And I want to solve for x.
When I set that derivative equal to zero, can i just multiply 0 by 2x, leaving x-3=0? So x=3

Homework Equations



none

The Attempt at a Solution


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  • #2
That should be ok. You could also divide the left side by x / x, assuming that x is not equal to zero, resulting in:

( 1 - (3/x) ) / 2 = 0
 
  • #3
thank you
 
  • #4
rcgldr said:
That should be ok. You could also divide the left side by x / x, assuming that x is not equal to zero, resulting in:

( 1 - (3/x) ) / 2 = 0

i thought they're supposed to show the work?
 
  • #5
MGCLO said:
i thought they're supposed to show the work?

It is a requirement for HW problems, but my question was geared towards a concept. The equation I'm deriving for the HW would probably take up an entire line on here. The example I put on was just that, an example, it wasn't even close to my actual problem (although I wish it was haha)
 
  • #6
MGCLO said:
i thought they're supposed to show the work?
Multiplying both sides by 2x is just as valid as dividing the left side by x/x. I only showed that as an alternative in case there's a situation where that would be a better option for a different equation.
 

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