Setting Up Triple Integral for Region Bounded by x=y^2, z=0, x+z=1

stratusfactio
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Homework Statement


Set up the triple integral for the region bounded by:

x=y^2, z=0, x+z=1

Homework Equations


The Attempt at a Solution


y= ±sqrt(x); z=0 & z=x+1
I'm just lost on how to find the x integral. I know the dz integral goes from z=0 to z=x+1, and I know the dy integral goes from y=-sqrt{x} to +sqrt{x}. I also know if we set 0=x+1, we get x=1, but how do I find the remaining limit of integration?
 
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Hi stratusfactio! :smile:

Your maximum z is a little off, it should be 1-x.

As for x, what's wrong with 0 to 1?
(I suggest you try to make a drawing.)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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