Shaft Angular velocity question

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SUMMARY

The discussion focuses on calculating various parameters related to the angular velocity of a rotating shaft with a diameter of 0.25 meters, initially rotating at 3000 revolutions per minute (rev/min). The angular velocity was determined to be 314.2 rad/s, and the angular acceleration required to increase the speed to 5000 rev/min in 90 seconds was calculated as 2.33 rad/s². The participant sought assistance specifically for calculating the linear speed of a point on the shaft's circumference, which can be derived using the relationship between linear speed and angular velocity.

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andycampbell1
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Hi
Doing some revising for my exams with past papers. I just need some help to begin this question.

Q
The shaft of diameter 0.25 is rotating at 3000 rev/min Determine
a) The angular velocity
b) The linear speed of a point on the circumference of the shaft
c) The angular acceleration required to increase the shaft speed to 5000 rev/min in a period of 90 seconds
d) The linear acceleration of a point on the circumference of the shaft.


Homework Equations



\omega2=\omega1+\alphat.


\theta=\omega1t+1/2 \alphat2.

\omega22=\omega12+ 2\alpha\theta

\theta=S/R

\omega=V/r

\alpha=a/r

I have converted the revs per mins to rad/s2 using 2pi(3000)/60 and attained the answer 314.2 rad/s2 for question (a) and for question (c) I have calculated the angular acceleration as 2.33 rad/s. I done this by converting 5000 rpm to rad/s which gave me 523.6 rad/s. To calculate the angular acceleration I subtracted the original velocity 314.2 from 523.6 rad/s and got the answer 209.4 which I divided by 90s which gave me 2.33. I would like help on how to begin question b, I have no idea how to start this question.
 
Last edited:
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Remember, your units of angular velocity are rad/s (not rad/s^2).

For part (b), try the 5th equation you listed.
 

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