Shear force and Bending moment of a Cantilever Rod

[kgprice11]

1. I have a rod as pictured in the attachment. The rod is at a 45 degree angle.
The load force is 115.118lbf
The force is y-direction is 97.954lbf

The Force at A is 5 inches from Force in the y-direction.
The force at B is 10.5 inches from the Force in the y-direction

I need to find the shear forces for A and B and the moment at point C

I am stuck at the shear forces (V)

Thanks for the help

 

[kgprice11]

Plz help I messed up here

 

[nvn]

kgprice11: You must list relevant equations yourself, and show your work. And then someone might check your math.

 

[pongo38]

You will not be able to find the shear forces at A and at B. But you will be able to find the shear force between A and B. Which definition of shear force do you prefer to use? (there are at least two)

 

[DeeNos]

I would first like to commend you for providing detailed information about your problem. This makes it easier for me to understand the situation and provide a response.

To find the shear forces at points A and B, we need to consider the equilibrium of forces along the rod. Since the rod is at a 45 degree angle, we can resolve the load force of 115.118lbf into its vertical and horizontal components. The vertical component will be equal to the force in the y-direction, which is 97.954lbf, and the horizontal component will be equal to 97.954lbf (115.118lbf x cos 45 degrees).

Now, for point A, we can apply the equilibrium equation: ΣFy = 0. This means that the sum of all vertical forces acting on point A must be equal to 0. Since we already know that the vertical component of the load force is 97.954lbf, we can deduce that the shear force at point A must be equal to the negative of this value, which is -97.954lbf.

Similarly, for point B, we can apply the same equation and find that the shear force at point B must be equal to -97.954lbf as well.

Moving on to finding the moment at point C, we need to consider the moment equation: ΣM = 0. This means that the sum of all moments acting on point C must be equal to 0. Since we know the force at A (97.954lbf) and its distance from point C (5 inches), we can calculate the moment at point C as follows:

ΣM = 0
(97.954lbf)(5 inches) - (Force at C)(10.5 inches) = 0
(97.954lbf)(5 inches) = (Force at C)(10.5 inches)
Force at C = (97.954lbf)(5 inches) / (10.5 inches)
Force at C = 46.641lbf

Therefore, the moment at point C is equal to 46.641lbf.

I hope this helps you in finding the shear forces at points A and B and the moment at point C. If you are still stuck, I would suggest seeking assistance from a qualified engineer or consulting a textbook on mechanics of materials.