Shear stress at different points of beam

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SUMMARY

The discussion focuses on calculating shear stress at points F and G on a beam using the formula $$ \tau = \frac{VQ}{It} $$, with a maximum shear force (V) of 205 kN and a moment of inertia (Ixx) of 2.1 x 10^-4. The calculations for Q at points F and G involve specific dimensions and require careful consideration of the web thickness and cut orientation for accurate results. The consensus is that the user must ensure the correct application of the shear stress formula and the appropriate geometric parameters for each point.

PREREQUISITES
  • Understanding of shear stress and its calculation in beams
  • Familiarity with the formula $$ \tau = \frac{VQ}{It} $$
  • Knowledge of beam cross-section properties, including moment of inertia (Ixx)
  • Ability to interpret geometric dimensions relevant to shear stress calculations
NEXT STEPS
  • Review the principles of shear force and bending moment in beam theory
  • Learn about the significance of web thickness in shear stress calculations
  • Study the effects of different cut orientations on shear stress determination
  • Explore advanced topics in structural analysis, such as shear flow and stress distribution
USEFUL FOR

Engineering students, structural analysts, and professionals involved in beam design and analysis will benefit from this discussion, particularly those focusing on shear stress calculations in structural engineering.

fonseh
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Homework Statement


i'm not sure how to calculate the shear stress at point F and point G . I know that shear stress has formula of $$ \tau = VQ/It $$

The maximum shear force that i calculated earlier is V = 205kN , Ixx = 2.1x10^-4

for Q at $$\tau$$ at F , i have (205x10^3)(260x10^-3)(50x10^-3)(98.5-25)(10^-3) / (2.1x10^-4)(260x10^-3)

for Q at $$\tau$$ at G , i have (205x10^3)(250x10^-3)(50x10^-3)(50+125-98.5)(10^-3) / (2.1x10^-4)(260x10^-3)

Is my ans correct ?

Homework Equations

The Attempt at a Solution


The maximum shear force that i calculated earlier is V = 205kN , Ixx = 2.1x10^-4

for Q at $$\tau$$ at F , i have (205x10^3)(260x10^-3)(50x10^-3)(98.5-25)(10^-3) / (2.1x10^-4)(260x10^-3)

for Q at $$\tau$$ at G , i have (205x10^3)(250x10^-3)(50x10^-3)(50+125-98.5)(10^-3) / (2.1x10^-4)(260x10^-3)

Is my ans correct ?

I'm not sure whether my Q , and t correct or not . Can anybody check for me ?
 
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At G, you should be looking at the web thickness for vert shear stress at horiz cut, otherwise ok. At F , however, you should be taking a vertical cut for horiz shear stress determination.
 

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