Shear stress at the boundary of beam

Click For Summary

Discussion Overview

The discussion revolves around determining the shear stress at point G in a beam using the formula $$\tau = VQ/ It $$. Participants explore how to calculate the area (Ay) and centroid relevant to this calculation, particularly in relation to the dashed line that adds confusion regarding which area to consider for Q. The conversation includes technical reasoning and calculations related to shear stress, as well as considerations of vertical and horizontal shear stresses.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant expresses confusion about how to determine Ay and which area to consider for Q, specifically questioning whether to use the area to the left or right of point G.
  • Another participant confirms the initial approach is correct but notes a minor error in the calculation regarding the value used for the centroid.
  • There is a discussion about the implications of using the area to the right of the dashed line, which could lead to calculating horizontal shear stress without accounting for vertical shear stress in the flange.
  • Participants discuss the relationship between vertical and horizontal shear stresses in different areas of the beam, suggesting that the total shear stress at G should theoretically be consistent regardless of the method used.
  • One participant questions whether the relationship between vertical and horizontal shear stresses is conceptual or requires calculation to confirm.
  • Another participant explains that for thin flanges, the vertical shear stress can be considered negligible due to the small area and large thickness used in calculations, referencing the behavior of shear stress in wide flange I beams.

Areas of Agreement / Disagreement

Participants generally agree on the validity of the initial calculation method but express differing views on the implications of using different areas for Q and the treatment of vertical versus horizontal shear stresses. The discussion remains unresolved regarding the best approach to account for these stresses.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the areas considered for shear stress calculations and the definitions of vertical and horizontal shear stresses. The implications of using different areas for Q and the resulting shear stress calculations are not fully resolved.

fonseh
Messages
521
Reaction score
2

Homework Statement


We all know that $$\tau = VQ/ It $$
how to determine the shear stress at **G** ?
I'm having problem of finding Ay
centroid if the solid that i found earlier is y = 98.5mm

There's a dashed line from G to the bottom . It's making me confused . for Q , should i consider the area either to the left or right of the G ? like the red and orange part

Homework Equations

The Attempt at a Solution


so , my working is
Q = Ay = (250x10^-3)(50x10^-3)( 50+125-98)(10^-3) = 9.63x10^-4

Is my concept correct ?
I'm considering the area above the G .
[/B]
 

Attachments

  • DSC_0049.JPG
    DSC_0049.JPG
    23.3 KB · Views: 429
  • dsc0050.jpg
    dsc0050.jpg
    33.7 KB · Views: 446
  • dsc0051.png
    dsc0051.png
    63.8 KB · Views: 467
Physics news on Phys.org
fonseh said:

Homework Statement


We all know that $$\tau = VQ/ It $$
how to determine the shear stress at **G** ?
I'm having problem of finding Ay
centroid if the solid that i found earlier is y = 98.5mm

There's a dashed line from G to the bottom . It's making me confused . for Q , should i consider the area either to the left or right of the G ? like the red and orange part

Homework Equations

The Attempt at a Solution


so , my working is
Q = Ay = (250x10^-3)(50x10^-3)( 50+125-98)(10^-3) = 9.63x10^-4

Is my concept correct ?
I'm considering the area above the G . [/B]
Yes, excellent work, that is the best way to do it. If the flanges were thinner, you could use the orange area and calculate the horizontal shear stress in the lower flange, and get the same result, but that doesn't work well for thick flanges, so your method and answer is correct, except you used 98 instead of 98.5 on your calc, no big deal.
 
  • Like
Likes   Reactions: fonseh
why
PhanthomJay said:
Yes, excellent work, that is the best way to do it. If the flanges were thinner, you could use the orange area and calculate the horizontal shear stress in the lower flange, and get the same result, but that doesn't work well for thick flanges, so your method and answer is correct, except you used 98 instead of 98.5 on your calc, no big deal.
there's a dashed line over there ? it makes me confused ...
 
fonseh said:
why

there's a dashed line over there ? it makes me confused ...
Yes it is confusing. If you use the area to the right of the dashed line and calculate Q using that area times the distance from its centroid to the horizontal neutral axis , you calculate the horizontal shear stress , but this calculation does not include the vertical shear stress in that flange,which although small, adds to the shear stress value.
 
PhanthomJay said:
Yes it is confusing. If you use the area to the right of the dashed line and calculate Q using that area times the distance from its centroid to the horizontal neutral axis , you calculate the horizontal shear stress , but this calculation does not include the vertical shear stress in that flange,which although small, adds to the shear stress value.
It's not stated in the question , right ? How to know what to find ? vertical shear stress or horizontal shear stress ?
 
fonseh said:
It's not stated in the question , right ? How to know what to find ? vertical shear stress or horizontal shear stress ?
The shear stress in the green area is vertical only, with its complimentary longitudinal shear stress. The shear stress in the orange area is both vertical/longitudinal and horizontal/longitudinal, which, when summed properly, should in theory equal the longitudinal shear stress calculated for the green area at G.
 
  • Like
Likes   Reactions: fonseh
PhanthomJay said:
he shear stress in the orange area is both vertical/longitudinal and horizontal/longitudinal, which, when summed properly, should in theory equal the longitudinal shear stress calculated for the green area at G.
Do you mean the sum of both vertical shear stress and horizontal shear stress = vertical shear stress of green part ?
 
fonseh said:
Do you mean the sum of both vertical shear stress and horizontal shear stress = vertical shear stress of green part ?
yes, which is the same as saying that the sum of both the longitudinal shear stress (due to vert shear stress in flange)and long shear stress (due to horiz shear stress in flange) is equal to the long shear stress in green part (due to vert shear stress in green part).
 
  • Like
Likes   Reactions: fonseh
PhanthomJay said:
yes, which is the same as saying that the sum of both the longitudinal shear stress (due to vert shear stress in flange)and long shear stress (due to horiz shear stress in flange) is equal to the long shear stress in green part (due to vert shear stress in green part).
How do you know that ? It's a concept or we need to do the caluclation to know it ? Is it possible to know it without calculation ?
 
  • #10
Regardless of calculation of shear stress at G, it should be the same no matter which method is used. But it is a lot easier to use the green area for the calc, as it avoids the complications that you get when using the orange area. If the flange was thin, say 5 mm instead of 50 mm, then either method could be used without complication, because there would essentially be no vert shear stress in flange. But the flange is not thin here, so your original method using the green area is best.
 
Last edited:
  • Like
Likes   Reactions: fonseh
  • #11
PhanthomJay said:
Regardless of calculation of shear stress at G, it should be the same no matter which method is used. But it is a lot easier to use the green area for the calc, as it avoids the complications that you get when using the green area. If the flange was thin, say 5 mm instead of 50 mm, then either method could be used without complication, because there would essentially be no vert shear stress in flange. But the flange is not thin here, so your original method using the green area is best.
Can you explain why when the flange is thin , the vertical shear stress in the flange can be ignored ?
 
  • #12
well, shear stress is (VQ/It), and Q is A(y_bar) ,and since with a thin flange Q is rather small since A is so small, and since t is rather large since you use the flange width, b, for the t value, then the shear stress is very small since A is small and t is large. look at a wide flange I beam for example, you can see how small is the vert shear stress in the flange, it then sharply increases in the web at the web interface since now t is web thickness instead of b flange width.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 4 ·
Replies
4
Views
13K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
4K
Replies
7
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K