1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Shielding an off-center charge with a conducting shell

  1. Oct 24, 2016 #1
    Hi.

    I'd like to show that a conducting, charged spherical shell can shield the field of an inside opposite point charge even if this charge is not at the center. I was thinking about a Gaussian surface just outside the sphere, such that if there were electric field vectors they would be perpendicular to the surface.

    I'd now like to show that all those field vectors either point inwards or outwards. Then I could use Gauss's law and show that the field vectors are in fact zero (since the total charge inside is zero). But I can't see why this is true. Couldn't the inside charge maybe induce a dipolar charge distribution on the outside of the sphere if it were really close to sphere?
     
  2. jcsd
  3. Oct 24, 2016 #2

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    It does! This is exactly what cancels the asymmetry from the charge inside.

    The outer surface of the shell is an equipotential surface. You can use symmetry to find an electric field that fits.
     
  4. Oct 25, 2016 #3
    Hi.

    I assume you're talking about placing a mirror charge outside to make the potential constant on the sphere? I know this method, but I was looking for a simpler way and hoped Gauss might help. I only want to show that the outside field vanishes, not how the inside field looks like.

    But the electric field produced by the outside mirror charge is only meaningful on the inside of the sphere, not on the outside, isn't it? At least this is what Wikipedia says, for the potential though.

    I might be asking for too much, but would you mind drawing a rough sketch about how the charges distribute on the outer and inner surface of the sphere?
     
  5. Oct 26, 2016 #4

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    No.

    You don't need any mirror charges here.

    Outside the spherical shell, the situation is symmetric and you know the total charge. There is exactly one possible electric field geometry that fits to this situation. If you don't care about the inside you don't have to find the charge distribution there.
     
  6. Oct 27, 2016 #5
    Ah okay, you mean the fact that the potential is constant on the sphere makes the situation symmetric and defines the field by uniqueness.
    You agreed that there will be a non-constant (even dipolar) charge distribution on the outside of the sphere. How can I find this distribution?
     
  7. Oct 27, 2016 #6

    mfb

    User Avatar
    2016 Award

    Staff: Mentor

    Sorry, misread the quoted part. The non-constant charge distribution is on the inside of the sphere.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Shielding an off-center charge with a conducting shell
Loading...