SHM Motion Q: Find Block's Speed at Position(s)?

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The discussion centers on a physics problem involving a block on a spring, where the block is pulled 20 cm and released, leading to oscillations with a period of 0.80 s. The main confusion arises regarding the definition of amplitude, as the textbook uses 20 cm as the amplitude based on the initial displacement. It is clarified that in an idealized scenario without friction, the block will oscillate back to the 20 cm mark, making it the amplitude. However, if the block were given an initial velocity, the amplitude could differ from the initial stretch. The conversation emphasizes the importance of energy conservation in determining the amplitude in ideal conditions.
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There's an example question from my textbook that I'm confused about:

A 500 g block on a spring is pulled a distance of 20 cm and released. The subsequent oscillations are measured to have a period of 0.80 s. At what position or positions is the block's speed 1.0 m/s?

The book solves this problem by using 20 cm as the amplitude. What I don't understand is, how do we know that this is the amplitude? I know it's stretched that far but couldn't the amplitude result in something different?
 
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The spring is stretched 20 cm. Assuming energy is conserved, Your block will always oscilate back to the 20cm mark. The question assumes the idealized situation of no friction. Immagine the block on a cart or frictionless airtrack. If you were to stretch the spring to 20cm and give the cart some initial velocity, you would have some amplitude other than 20cm.
 
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