- #1
unhip_crayon
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Homework Statement
A block, attached to a spring, moves in Simple Harmonic Motion on a horizontal frictionless
table. The displacement from equilibrium is given by x = xm cos (ω t + φ ) where x is positive to
the right of the equilibrium position. The frequency of the motion is 3.10 Hz and the amplitude
is 15.0 cm. At t = 0.00 s, the velocity of the block is 2.70 m/s to the left and the position is to the
left of the equilibrium position.
Calculate the phase angle, φ.
Answer: 1.96 Rad
I have no Idea what I'm doing wrong. I am almost certain its a stupid mistake
The Attempt at a Solution
xm=0.15m
w=2[tex]\pi[/tex]f
w=19.478
V=wx
2.7=19.478x
x=0.139
t=0
now I just plugged and chugged it all into x = xm cos (ω t + φ )
but i got the wrong answer...help please