# Shock wave

1. Dec 3, 2005

### lilkrazyrae

What is the shock wave cone half-angle for a supersonic airplane flying at Mach 2.30?

Would you use Mach=1/sin(theta) and then divide by 2 to get the half angle?

So 2.30=1/sin(theta)=12.9 degrees

2. Dec 4, 2005

### FredGarvin

$$sin\theta = \frac{1}{M}$$

So take the inverse sin of 1/M and you get the half angle. There is no need to divide by 2.