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Shock wave

What is the shock wave cone half-angle for a supersonic airplane flying at Mach 2.30?

Would you use Mach=1/sin(theta) and then divide by 2 to get the half angle?

So 2.30=1/sin(theta)=12.9 degrees
 

FredGarvin

Science Advisor
5,050
6
[tex]sin\theta = \frac{1}{M}[/tex]

So take the inverse sin of 1/M and you get the half angle. There is no need to divide by 2.

http://www.adl.gatech.edu/classes/dci/hispd/dci09.html [Broken]
 
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