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What is the shock wave cone half-angle for a supersonic airplane flying at Mach 2.30?
Would you use Mach=1/sin(theta) and then divide by 2 to get the half angle?
So 2.30=1/sin(theta)=12.9 degrees
Would you use Mach=1/sin(theta) and then divide by 2 to get the half angle?
So 2.30=1/sin(theta)=12.9 degrees