Short (I think) vector calculus question

HmBe
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Homework Statement



Calculate the following expressions:

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Homework Equations



The Attempt at a Solution



Letting the vector a = (a_1, a_2, a_3) I've worked out that it's 2|a|^2

While that method is fairly quick, I don't particularly like it, and was wondering if there is a shorter or neater method using identities and such, perhaps using del^2 = del . del, then using div and grad identities? Cheers.
 
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You could work it out as div(grad((a.r)^2)), but it amounts to doing the pretty much the same thing you just did.
 
Yeah, that's what I thought. But wasn't sure if there was a way to simplify grad((a.r)^2)
 
HmBe said:
Yeah, that's what I thought. But wasn't sure if there was a way to simplify grad((a.r)^2)

grad((a.r)^2)=2(a.r)*grad(a.r)=2(a.r)a. div(2(a.r)a)=a.grad(2(a.r))+2(a.r)div(a)=2a.a+0=2a.a. You can write down all the steps with vectors, but I really don't think it's saving much time.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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