Proving 1 ppm = 1 mg/L: Conflicting Equations?

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The discussion centers on the equivalence of 1 ppm and 1 mg/L, particularly in the context of water solutions where 1 liter of water is approximately 1 kilogram. The user presents conflicting equations regarding the definitions of concentration in ppm and mg/L, expressing confusion over their relationship. It is clarified that 1 ppm is defined as 1 mg of solute per 1 kg of solvent, which aligns with the assumption that 1 L of water weighs about 1 kg. The key point is that the apparent conflict arises from not accounting for the mass of the solvent when using the ppm formula. Ultimately, the equivalence holds true under the specified conditions.
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My text claims that 1 ppm = 1 mg/L. I tried to prove this for myself but I seem to be stuck. This is what I have so far:

1 mg(solute)/L(solvent) = 1 mg(solute) / 1*10^6 mg(solvent)

But:

C(ppm) = (mass solute)/(mass solvent) *10^6 ppm

These seem to be in conflict, what am I not seeing?
 
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1 ppm = 1 mg/L for water solutions, when you can assume mass of 1L to be close to 1 kg.
 
Yes, but how can it be proved?
 
1 mg/1 kg = 10-6, I am not sure where the problem is.
 
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