Show that if a is greater than or equal to the degree of minimal polyn

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Homework Statement


Show that if a is greater than or equal to the degree of minimal polynomial (say k), then L^a is a linear combination of 1v,L,…,Lk−1

If L is invertible, show the same for all a<0


Homework Equations


about minimal polynomial
http://en.wikipedia.org/wiki/Minimal_polynomial_(linear_algebra )


The Attempt at a Solution


i know a few things about minimal polynomial, i know what linear combination, invertible means but i have no clue how to start this problem.

i think the most confusing part i find is that i don't know how to deal with
L^a and the 1_v,L,...,L^k-1
 
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catsarebad said:

Homework Statement


Show that if a is greater than or equal to the degree of minimal polynomial (say k), then L^a is a linear combination of 1v,L,…,Lk−1

If L is invertible, show the same for all a<0


Homework Equations


about minimal polynomial
http://en.wikipedia.org/wiki/Minimal_polynomial_(linear_algebra )


The Attempt at a Solution


i know a few things about minimal polynomial, i know what linear combination, invertible means but i have no clue how to start this problem.

i think the most confusing part i find is that i don't know how to deal with
L^a and the 1_v,L,...,L^k-1


Read my response to your other question about minimal polynomials.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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