MHB Show that the codeword a cannot be a valid codeword.

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In a Hamming (7,4) code, the minimum Hamming distance is 3, meaning that any two valid codewords must differ in at least 3 bits. When considering a codeword d that differs from another codeword a at precisely 2 bits, it violates the minimum distance requirement. Therefore, codeword a cannot be a valid codeword in this coding scheme. The Hamming distance of 3 ensures that valid codewords must differ by at least this amount, confirming that a codeword differing by only 2 bits is invalid.
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Let d=d1d2d3d4d5d6d7 be a valid codeword of Hamming (7,4) code. Suppose a=a1a2a3a4a5a6a7 be another codeword that differs from d precisely at two bits. Show that the codeword a cannot be a valid codeword.

May I ask how to solve this type of problem?
 
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what's the Hamming distance of the (7,4) code? (hint: it's 3)

Can a valid codeword exist at a Hamming distance of 2 bits in a code with a Hamming distance of 3?
 
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