Show that the wavefunction is normalized

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The discussion revolves around demonstrating the normalization of the angular wavefunction Θ_{20} given by the equation Θ_{20} = (√10/4)(3cos²θ - 1). The user is seeking guidance on setting up the integral to show that this wavefunction satisfies the normalization condition, specifically the integral from 0 to π of |Θ_{20}(θ)|²sinθ dθ equating to 1. They express uncertainty about the normalization process, indicating that their current studies have not covered complex methods. The conversation emphasizes the importance of correctly setting up the integral to prove normalization.
Von Neumann
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Problem:

Show that

\Theta_{20}=\frac{\sqrt{10}}{4}(3cos^{2}\theta-1)

is a normalized solution to

\frac{1}{sin\theta}\frac{d}{d\theta}(sin\theta \frac{d\Theta}{d\theta})+[l(l+1)-\frac{m_{l}^{2}}{sin^{2}\theta}]\Theta=0

Solution:

I know how to show it's a solution, but I'm stuck on showing it's normalized.

I know that in general, a normalized wavefunction obeys,

\int^∞_{-∞}\mid \psi \mid^{2}dV=1

So would this particular normalized angular wavefunction obey the following?

\int^{\pi}_0\mid \Theta_{20}(\theta) \mid^{2}\sin\theta d\theta=1

I'm sorry if this is very elementary, but we just started doing this type of thing in my modern physics class. We haven't used any complex methods to solve these, so I don't think this problem will involve any advanced operators or anything of that sort. Any suggestions?

I just need help setting the integral up.
 
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Von Neumann said:
So would this particular normalized angular wavefunction obey the following?

\int^{\pi}_0\mid \Theta_{20}(\theta) \mid^{2}\sin\theta d\theta=1

Exactly.
 
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