Showing A Matrix Property Is True

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Homework Statement


Let A be an invertible matrix. Show that (A^n)^{-1} = (A^{-1})^n


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The Attempt at a Solution


I want to begin on the left side of the equality sign; but I am having a little difficulty on expanding it. I started to--(A^n)^{-1} = AAA...A^{-1}--but it just didn't appear correct. Could someone help me?
 
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I would be inclined to prove it using "induction". If n= 1, this just says that (A)^{-1}= A^{-1}. Now, suppose (A^k)^{-1}= (A^{-1})^k. What can you say about (A^{k+1})^{-1}= ((A^k)A)^{-1}?

(You will need to prove separately that (AB)^{-1}= B^{-1}A^{-1}.)

By the way, you have
want to begin on the left side of the equality sign; but I am having a little difficulty on expanding it. I started to--(An)−1 =AAA...A−1 --but it just didn't appear correct. Could someone help me?
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No, that is not correct. (An)-1 is the multiplicative inverse of An: (An)(An)-1= I.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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