Showing that g^-1 H g is a subgroup

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Homework Statement


If H is a subgroup of G, show that g^{-1}Hg={g^{-1}hg \; h\in H is a subgroup for each g\in G


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The Attempt at a Solution



I know I just have to check for closure and inverses, but the elements in this group g^{-1}hg with different h or with different g?
 
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Same g for all of them but different h's in H.
 

Thread 'Finding the nth roots of a complex number'

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