Showing that S^2 and Sz Commute with the System Hamiltonian

AI Thread Summary
To demonstrate that S^2 and Sz commute with the Hamiltonian H for a system of two spins, the Hamiltonian can be expressed in terms of the total spin S. The relationship S^2 = S1^2 + S2^2 + 2S1·S2 is crucial, where S1·S2 can be rewritten using the total spin operator. The simplification involving the values of S1^2 and S2^2 as 3/4 is a common approach, but the key requirement is to show that the commutation relations [H, S^2] and [H, Sz] hold. The discussion emphasizes that detailed simplification is unnecessary; the focus should be on proving the commutation properties.
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Homework Statement



A system with two spins of magnitude 1/2 have spin operators S1 and S2 and total spin S = S1 + S2

B is a B-field in the z direction (0,0,B)

The Hamiltonian for the system is given by H = m S1 . S2 + c B.S where m,c are constants.


By writing the Hamiltonian in terms of S, show that S^2 and Sz commute with the hamiltonian.

Homework Equations





The Attempt at a Solution



So i know that S^2 = S1 ^2 + S2 ^2 + 2S1.S2

so S1.S2 can be written as 1/2 (S^2 - S1 ^2 - S2 ^2)

But how do i simplify this?

My guess is that I can replace each of S1^2 and S2 ^2 with 3/4..but is this right? why is it justified? if not, what do i do?

Thanks
 
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You don't need to simplify. You just have to show that [H,S^2]=[S^2,H] and same for Sz. You should really post this in advanced physics.
 
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