Showing that some functions are solutions to a diff eq.

  • Thread starter Thread starter Duderonimous
  • Start date Start date
  • Tags Tags
    Diff eq Functions
Duderonimous
Messages
63
Reaction score
1

Homework Statement


Show that y1(t) and y2(t) are solutions to a certain differential equation.

Homework Equations


The Attempt at a Solution



I plug both of these into my diff. eq. and I got the same thing. How is this showing that they are solutions to a diff. eq.? What if I got a different answer when I plugged in each function, what would that mean?

I omitted the details because I thought this ws more of a concept question. THanks

I think I answered my own question, I took the derivative of the solns and they equaled what I got when I plugged the solns into the diff. eq. :)
 
Last edited:
Physics news on Phys.org
You are asking a very general question. Why don't you provide a complete problem statement along with your work?
 
Duderonimous said:

Homework Statement


Show that y1(t) and y2(t) are solutions to a certain differential equation.

Homework Equations





The Attempt at a Solution



I plug both of these into my diff. eq. and I got the same thing.
What do you mean by "got the same thing". The question is whether the two functions separately satisfy the differential equation. When you put y1 into the equation are both sides the same?

How is this showing that they are solutions to a diff. eq.? What if I got a different answer when I plugged in each function, what would that mean?

I omitted the details because I thought this ws more of a concept question. THanks

I think I answered my own question, I took the derivative of the solns and they equaled what I got when I plugged the solns into the diff. eq. :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top