Showing that U = {(x, y) | xy ≥ 0} is not a subspace of R^2

  • Thread starter Thread starter pakkanen
  • Start date Start date
  • Tags Tags
    Subspace
pakkanen
Messages
11
Reaction score
0

Homework Statement


Task: Show that U = {(x, y) | xy ≥ 0} is not a subspace of vector space R2

I wish you could help me to understand why U is not a subspace of R2x2.

I have actually found a vectors u and v such that it does not belong to U (e.g. (-3,-1) +(2,2) = (-1,1) ) but is that sufficient to show that U is not a subset of R2x2?
 
Physics news on Phys.org
pakkanen said:

Homework Statement


Task: Show that U = {(x, y) | xy ≥ 0} is not a subspace of vector space R2

I wish you could help me to understand why U is not a subspace of R2x2.

I have actually found a vectors u and v such that it does not belong to U (e.g. (-3,-1) +(2,2) = (-1,1) )
What does "it" refer to? are you trying to show that the sum of two vectors in the set may not be in the set? If so, yes, that is valid.

but is that sufficient to show that U is not a subset of R2x2?
Well, first, you are not trying to show U is not a subset. It is. But it is not a subspace. I suspect that was a typo. Yes, this is sufficient. To be a subspace, the subset must satisfy a number of properties. If it fails to satisfy anyone of them it is not a subspace.

Homework Statement


Homework Equations


The Attempt at a Solution

 
Sorry for being unclear. I meant the subspace and not subset as you mentioned. And now it became a clear for me. Thank you very much!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top