Showing union of open sets is an open set?

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Homework Statement



Let U_n = {all p = (x, y) with |p - (0, n)| < n}. Show that the union of all the open sets U_n, for n = 1, 2, 3, ..., is the open upper half plane.

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The Attempt at a Solution



U_n describes points p whose distance from a set point on the vertical axis is smaller than the height of that point that is on the vertical axis. When you move the vertical axis point up and down, and combine all the sets of points created, you'll get the upper half plane not including the horizontal axis. I can picture it, but how do I begin to show it?
 
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Pick a point in the upper half plane p=(x,y) with y>0. Can't you figure out a way to find an n large enough the p is in the circle centered at (0,n) with radius n? This really isn't conceptually hard. n can be as large as you like. Figure out the intersection of the circle with the vertical line through the point. Make it less than y.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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