Sign Convention - Physics - Optics

AI Thread Summary
In optics, according to the Gaussian sign convention, a positive image distance (Si > 0) indicates a real, inverted image. Conversely, a negative object distance (So < 0) suggests a virtual, upright image. The discussion confirms that these interpretations hold true when applying the thin lens equation. The clarification emphasizes the importance of understanding the sign conventions in optics for accurate image characterization. This knowledge is essential for anyone studying or working in the field of physics and optics.
rajiv_putcha
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[SOLVED] Sign Convention - Physics - Optics

I was just looking at some sign conventions and I was wondering if this is true:

Along the principle axis, if Si > 0, then does that mean you have a real, inverted image?

Also along the principle axis, if So < 0, then does that mean you have a virtual, upright image?

Thanks in Advance!
 
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rajiv_putcha said:
I was just looking at some sign conventions and I was wondering if this is true:

Along the principle axis, if Si > 0, then does that mean you have a real, inverted image?
If you're talking about the typical Gaussian sign convention for a thin lens (where the thin lens equation is 1/S_i + 1/S_o = 1/f) and a typical real object (So > 0), then yes.

Also along the principle axis, if So < 0, then does that mean you have a virtual, upright image?
Assuming you meant Si < 0 (and with the above caveats), then yes again.
 
thanks alot!
 
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