Significance of standard form of 1st and 2nd order transfer functions?

In summary: Thanks for reading!In summary, I foolishly skipped most of my analogue electronics classes, and inevitably failed the exam. I'm now trying to revise for the resit but I'm so far behind that I just cannot understand any of the lecture slides, and I'm getting very stressed.
  • #1
CraigH
222
1
I foolishly skipped most of my analogue electronics classes, and inevitably failed the exam. I'm now trying to revise for the resit but I'm so far behind that I just cannot understand any of the lecture slides, and I'm getting very stressed.

The part of the module I am revising at the moment contains: transfer functions, poles and zeros, impulse response, step response, sine response, Bode plots, and frequency analysis.

I understand very little so I have many questions, but as I can't ask a whole modules worth of questions in a thread I thought I'd start with this:

What is the significance of the standard form of 1st and 2nd order transfer functions?

The standard form of a first order transfer function is:

(1) [tex]\tau \frac{dy}{dt} + y = k * x(t)[/tex]

The laplace transform of this:

(2) [tex]G(s) = \frac{Y'(s)}{X'(s)} = \frac{k}{\tau s+1}[/tex]

but sometimes it is given as

(3) [tex]H(s) = \frac{1}{\tau s +1} = \frac{a}{s+a}[/tex]

The standard form of a second order transfer function is:

(4) [tex]\tau ^{2} \frac{d^{2}y}{dt^{2}}+2 \tau \zeta \frac{dy}{dt} + y = k * x(t)[/tex]

The laplace transform of this:

(5) [tex]G(s) = \frac{Y(s)}{X(s)} = \frac{k}{\tau^2s^2 + 2\tau\zeta s+1}[/tex]

but sometimes this is given as

(6) [tex]H(s) = \frac{\omega_n^2}{s^2+2\zeta \omega_n s + \omega_n^2}[/tex]

Here are my questions:
  • What is the physical meaning of "first" and "second order"? (apart from the fact that the highest power of the differential in the first is 1 and in the second is 2). How do I know if a system is first or second order?
  • Where do equations (1) and (4) come from? Why were these decided to be the "standard form"? What is so special about this form and how were these equations derived?
  • When given a first order system, why is sometimes equation (2) given, and sometimes equation (3) as the transfer function for this system? Likewise, when given a second order system why is equation (6) usually given, when the laplace transform is actually equation (5)?

Thanks for reading!
 
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  • #2
CraigH said:
What is the physical meaning of "first" and "second order"? (apart from the fact that the highest power of the differential in the first is 1 and in the second is 2)
To get some physical insight, you should have a look at what kinds of systems you can model using first and second order linear differential equations with constant coefficients. A transfer function is just a tool we use to analyze these systems, but they're definitely not required. You could analyze them perfectly well without ever having to develop a transfer function.

CraigH said:
How do I know if a system is first or second order?
Are we talking purely mathematically? Just have a look at what order of differential equation the transfer function maps to and vice versa.

'Order' is a mathematical term. In practice, if you can approximately model your system as a first or second order system, then you might say something along the lines of "the system has first/second order dynamics", where it's understood that we're talking about a LTI approximation.

CraigH said:
Where do equations (1) and (4) come from? Why were these decided to be the "standard form"? What is so special about this form and how were these equations derived?
You tell me. Your (4) is unusual (the time constant of a second order system is given by [itex]\tau = \frac{1}{\zeta \omega_n}[/itex]). Usually you'll see it in (unforced) standard form as:
[tex]
\frac{{\mathrm{d}^2 x}}{{\mathrm{d}t}^2} + 2 \zeta \omega_n \frac{{\mathrm{d}x}}{{\mathrm{d}t}} + \omega_n^2 x = 0
[/tex]
They're special because the time constant, natural frequency and damping factor characterize the dynamics of these systems in a meaningful way. I can look at numbers for these quantities and immediately tell you something meaningful about how the system behaves. These direct forms are a convenience.

CraigH said:
When given a first order system, why is sometimes equation (2) given, and sometimes equation (3) as the transfer function for this system? Likewise, when given a second order system why is equation (6) usually given, when the laplace transform is actually equation (5)?
In (2) you see the time constant directly. In (3) you see the pole location directly. Your (4) is a bit wonky. (6) shows the natural frequency and damping factor directly.

They're all good for something. It's just a matter of convenience.
 
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  • #3
(2) G(s)=Y′(s)X′(s)=k/(τs+1)

but sometimes it is given as

(3) H(s)=1/(τs+1)=a/(s+a)
Looking at (2) you can see immediately that at low-frequency (DC) it has a gain of k. Looking at (3) you can tell at a glance that the system's gain has begun dropping off by 3dB (1/√2) when frequency = a radians/second (the constant in the denominator). These are two defining characteristics of any system.

As far as electronics goes, a first order system contains one storage element (either C or L), together with one or more resistors. A second order system contains some resistances together with twoǂ storage elements, either two C's or two L's or one of each.

ǂ capacitors in parallel count as only one element, the same applies to multiple L's

The differential equations arise because current is related to voltage for both C and L by a first-order equation.
 
  • #4
Here are my questions:

What is the physical meaning of "first" and "second order"? (apart from the fact that the highest power of the differential in the first is 1 and in the second is 2). How do I know if a system is first or second order?

You have it right - in Laplace one is linear the other is quadratic
Where do equations (1) and (4) come from? Why were these decided to be the "standard form"? What is so special about this form and how were these equations derived?
1 and 4 are ordinary differential equations that you learned to solve in that math class you took, Differential Equations.. They describe something in the real world. Laplace transforms are just a tool that simplifies the solution of such equations.

When given a first order system, why is sometimes equation (2) given, and sometimes equation (3) as the transfer function for this system? Likewise, when given a second order system why is equation (6) usually given, when the laplace transform is actually equation (5)?
That is purely the author's choice.
As Miles Young pointed out, one form tells him a lot about the system's behavior. The other form might tell an electronics guy just what time constants he will need in order to create that function with operational amplifiers.
Both electronic and mechanical types recognize that a quadratic in the denominator makes a system potentially oscillatory - if the denominator can resolve to zero the system can have an output for no input. Hence the dreaded phrase "Real roots in denominator" ...

So an electronic oriented author may prefer one form and a mechanical oriented author might prefer the other.
An astute student will become fluent at transforming between the two forms so he is at home in both worlds, mechanical and electronic.

Sure it's a bit of work, but -
"When the going gets tough , the tough get going. "
 
  • #5


I understand that learning a new concept can be overwhelming, especially if you have missed important lectures and are trying to catch up. It is important to take a step back and understand the significance of the standard form of 1st and 2nd order transfer functions before delving into the specific equations.

The standard form of a transfer function is a mathematical representation of a system's behavior. In the case of transfer functions, it represents the relationship between the input and output of a system. The order of a transfer function refers to the highest power of the differential in the equation. A first order transfer function has a maximum of one derivative, while a second order transfer function has a maximum of two derivatives. This is important because it tells us how many poles and zeros the transfer function will have, which ultimately affects the system's behavior.

Equations (1) and (4) are derived from the general form of a transfer function, which is a differential equation of the form:

(7) \sum_{n=0}^{N} a_n \frac{d^{n}y}{dt^{n}} = \sum_{m=0}^{M} b_m \frac{d^{m}x}{dt^{m}}

where a_n and b_m are coefficients and N and M represent the order of the transfer function. The standard form equations are derived by setting the coefficients and orders to specific values, which simplifies the equation and makes it easier to analyze the system's behavior.

Equation (2) is usually used when the transfer function represents a physical system, such as an electrical circuit or a mechanical system. The equation includes a gain (k) and a time constant (\tau), which have physical interpretations in these systems. Equation (3) is a more general form and is often used in mathematical analysis.

Similarly, equation (6) is used for physical systems, where \omega_n represents the natural frequency of the system and \zeta represents the damping ratio. These parameters have physical meanings and can be used to analyze the system's response. Equation (5) is a more general form and is used in mathematical analysis.

In summary, the standard form of 1st and 2nd order transfer functions simplifies the analysis of a system's behavior and allows for easier interpretation of physical systems. It is important to understand the significance of this form before delving into the specific equations. I would recommend seeking help from your professor or
 

1. What is the significance of using standard form for 1st and 2nd order transfer functions?

The standard form of a transfer function allows for a more simplified and generalized representation of a system's response to input signals. This makes it easier to analyze and compare different systems and their behaviors.

2. How do you convert a transfer function to standard form?

To convert a transfer function to standard form, you need to factor out the highest power of the variable in the denominator and then divide the entire function by that factor. This results in a transfer function with a constant as the highest power in the denominator.

3. What are the benefits of using 1st and 2nd order transfer functions over higher order functions?

1st and 2nd order transfer functions are simpler and easier to analyze compared to higher order functions, which can have more complicated and unpredictable behaviors. Additionally, 1st and 2nd order functions can often provide sufficient accuracy for practical applications.

4. How are 1st and 2nd order transfer functions used in control systems?

1st and 2nd order transfer functions are commonly used to model and analyze control systems, as they can provide insight into the system's stability, response to disturbances, and overall performance.

5. Can standard form be applied to transfer functions with multiple inputs or outputs?

Yes, standard form can be applied to transfer functions with multiple inputs or outputs. Each individual transfer function can be converted to standard form separately, and the overall transfer function can be represented as a matrix of standard form transfer functions.

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