Significance of Surface and Coulomb Terms

genloz
Messages
72
Reaction score
1
I recently had a test question posed to me that asked firstly for an explanation of the terms in the semi empircal mass forumla (which I gave correctly) but then went on to ask:

For
^{40}_{20}Ca
and
^{208}_{96}Pb
estimate the fraction of the binding energy provided by the surface and coulomb terms, and comment on the significance of these results...

So I estimated:
Pb
Surface: 17.23*(208)^(2/3) = 604.868
Coulomb: (0.714*96^2)/(208^(1/3)) = 1110.58

Ca
Surface: 17.23*(40)^(2/3) = 201.52
Coulomb: (0.714*20^2)/(40^(1/3)) = 83.5

But could not work out at all what the significance was... I have a feeling the same question will be on the exam, so I was wondering if anyone could give me a clue please?
 
Physics news on Phys.org
Well I've found that for higher atomic numbers the surface and coulomb terms are almost equal to the binding energy, but they're subtracted from the volume term which makes me confused again...
 
Also how do I estimate total binding energy without the other terms?
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top