Simple Abstract Proof, with Matrices

kuahji
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Prove that the field R of real numbers is isomorphic to the ring of all 2 X 2 matrices of the form (0,0)(0,a), with a as an element of R. (Hint: Consider the function f given by f(a)=(0,0)(0,a).)

I have no problem showing that it is a homomorphism & that it's injective. My question arrises for showing that it's surjective.

Can't I just choose a matrix like (1,2),(3,4), & clearly that aint happening b/c you could never find f(r)=(1,2),(3,4). We did one in class like that, & that is what the professor stated, but here in the book it says to prove it. So now I'm wondering...
 
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It doesn't say R is isomorphic to the ring of ALL 2x2 matrices. It says it's isomorphic to the ring of all 2x2 matrices OF THE FORM (0,0),(0,a). (1,2)(3,4) isn't of that form.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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