Simple Derivative: e^nx Answer C

  • Thread starter Thread starter Qube
  • Start date Start date
  • Tags Tags
    Derivative
Qube
Gold Member
Messages
461
Reaction score
1

Homework Statement

http://k.minus.com/j4eToABCaFgrW.png

Homework Equations



The derivative of e^anything = e^anything * (du/dx).

The Attempt at a Solution



So, wouldn't the answer choice be C? The derivative of e^nx = (e^nx)(n).
 
Last edited by a moderator:
Physics news on Phys.org
Qube said:

Homework Statement

http://k.minus.com/j4eToABCaFgrW.png

Homework Equations



The derivative of e^anything = e^anything * (du/dx).

The Attempt at a Solution



So, wouldn't the answer choice be C? The derivative of e^nx = (e^nx)(n).
No, it's not answer (C). (C) is the first derivative !

Start by looking at \displaystyle \frac{d}{dx}e^{nx}\,,\ \ \frac{d^2}{dx^2}e^{nx}\,,\ \ \frac{d^3}{dx^3}e^{nx}\,, \ \ \text{etc.}
 
Last edited by a moderator:
Ohhh ... I get it :)! Thanks :D.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top