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Simple Derivitive

  • Thread starter Dr Game
  • Start date
26
0
It's been a while, but how would you go about deriving

[tex]y = C e^-^5^x[/tex]

and plug it into this equation

[tex]y'' + 4y' - 5y = 0[/tex]

i can do this without C the answer would be 0, but what do I do with C there?
 

cristo

Staff Emeritus
Science Advisor
8,056
72
You just differentiate it as usual, leaving the C in front of the terms, and then plug the first and second derivatives into the equation.
 
26
0
alright thought so, so I should get the same answer if C wasn't there, which is 0

[tex]25Ce^-^5^x+4(-5Ce^-^5^x)-5Ce^-^5^x = 0[/tex]
 

cristo

Staff Emeritus
Science Advisor
8,056
72
Yes, that's correct
 

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