- #1
Dr Game
- 26
- 0
It's been a while, but how would you go about deriving
[tex]y = C e^-^5^x[/tex]
and plug it into this equation
[tex]y'' + 4y' - 5y = 0[/tex]
i can do this without C the answer would be 0, but what do I do with C there?
[tex]y = C e^-^5^x[/tex]
and plug it into this equation
[tex]y'' + 4y' - 5y = 0[/tex]
i can do this without C the answer would be 0, but what do I do with C there?