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It's been a while, but how would you go about deriving
[tex]y = C e^-^5^x[/tex]
and plug it into this equation
[tex]y'' + 4y' - 5y = 0[/tex]
i can do this without C the answer would be 0, but what do I do with C there?
[tex]y = C e^-^5^x[/tex]
and plug it into this equation
[tex]y'' + 4y' - 5y = 0[/tex]
i can do this without C the answer would be 0, but what do I do with C there?