SIMPLE e&m question: finding equivalent capacitance

AI Thread Summary
To find the equivalent capacitance (C(eq)) of capacitors in series, the formula used is 1/C(eq) = 1/C(1) + 1/C(2). For capacitors of 6.0 µF and 3.0 µF, this calculation becomes 1/C(eq) = 1/6 + 1/3. Converting 1/3 to a common denominator gives 1/3 = 2/6, resulting in 1/C(eq) = 3/6. Inverting this fraction leads to C(eq) = 2.0 µF, confirming the calculation. The process illustrates the method for determining equivalent capacitance in series configurations.
offbeatjumi
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I am missing something very simple... in my book, it gives, for capacitors in series, that:

1/C(eq) = 1/C(1) + 1/C(2)
using numbers, it says...

1/C(eq) = 1/6.0 uF + 1/3.0 uF ... C(eq) = 2.0 uF

I cannot figure out how they got C(eq) = 2.0 uF

Thanks
 
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1/Ceq = 1/6 + 1/3 --> 1/6 + 2/6 = 3/6

3/6 = 1/2 = 1/ Ceq...

to find Ceq flip --> Ceq = 2uF
 

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