1. The problem statement, all variables and given/known data A block mass M slides down the side of a frictionless circle Radius R. At an angle Theta the mass M flies off the circle, what is the angle? 2. Relevant equations PE(top) = KE(point it flies off) + PE(at that point) Arad = V^2 / R Sum Of Forces = Mass * Acceleration 3. The attempt at a solution Okay I actually did this one before and I was trying to do it again but somehow I don't seem to be able to get it. The answer was Inverse Cosine of 1/1.5 or 48 degrees. The problem was done with energy equations PE(top) = KE(point) + PE(point) I set 0 PE to be the middle of the circle so mgR = .5 mv^2 + mg(Rcos(theta)) mass cancels gR = .5v^2 + gRcos(theta) I think I'm going wrong here but I said the only force acting on the block is weight or mg, because at the point is leaves the normal force goes to 0. so sum forces = mass * acceleration mg = ma mass cancels g = a then v^2 / R = a , so gR = V^2 then plugging that in gR = .5v^2 + gRcos(theta) gR = .5gR + gR cos(theta) gR cancels 1 = .5 + cos(theta) and I end up with 60 degrees so I think I missed out a number somewhere but I don't know where.