Calculating Muzzle Velocity of a Tank's Gun for a Uranium Projectile

[SamTsui86]

Homework Statement

A uranium projectile fired from a tank in Iraq has a volume of 351.00 cm3 and an intital kinetic energy of
2.00 × 103 kJ. What is the muzzle velocity of the tank's gun (m/s) ?

The density of uranium is 18.95 g/cm3

Homework Equations

Density = mass / volume

KE= 1/2 m v^2

The Attempt at a Solution

Using volume and density I figured out the mass
m = dv m = (18.95)(351) = 6651.45 g
plug in kinetic energy formula

KE = 1/2 m v^2 2000000 J = 1/2 6651.45 v^2

so v^2 is 601.37 and therefore v = 24.53 m/s

It kept saying that I am wrong, please help

 

[mukundpa]

Whether all quantities are taken same unit system?

what about gram and jule?

 

[m2003]

.

I would first like to acknowledge the effort put into solving this problem. Your calculations are correct, however, it is important to note that the given kinetic energy is in kilojoules (kJ) and not joules (J). This means that the value of 2.00 × 103 kJ should be converted to 2.00 × 106 J before plugging it into the equation. This would result in a final answer of approximately 245.29 m/s, which is closer to the expected answer. Additionally, it is important to consider any other factors that may affect the muzzle velocity of the tank's gun, such as air resistance or the weight of the tank itself, in order to obtain a more accurate result.