Simple fluids but is the application correct

In summary, the student was unable to find a solution to the homework equation due to the angle of the water surface on ice.
  • #1
phyeinstein_c
27
0

Homework Statement



problem states that ... there is a u tube and filled with liquid of densities ρ and 2ρ. the base length of the tube is 'l'. now it is accelerated towards right with accl.=a. if the HEIGHT DIFFERENCE AFTER ACCELERATING THE SYSTEM IS '0'. then what was the height difference before acceleration??

Homework Equations



P=ρgh; F=ma ; F=(ρ.V)a ;

The Attempt at a Solution


i tried to find pressure at bottom most level at interface of the two liquids, then the net force, then applied Newtons 2nd law, but could'nt get the solution...
 
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  • #2
hi phyeinstein_c! :smile:

hint: what will be the angle of the surface of the fluid (in either half of the 'U') ? :wink:
 
  • #3
lets see...if the u tube is moving towards right the major driving force is on the left side of the tube. since the heights are equal the 2p liquid is in the left tube .

first find relations between height h1 and h2 in the two sides of tube when at rest...then find height h when accelerated.. then keeping volume constant use h1 + h2 = 2h
 
  • #4
tiny-tim said:
hi phyeinstein_c! :smile:

hint: what will be the angle of the surface of the fluid (in either half of the 'U') ? :wink:
they're not at angle. initially they are at a height difference. that's it is wat is given.
 
  • #5
i know, i mean, suppose there was only one pipe (or a jar or vase), what would be the angle of the water surface? :wink:
 
  • #6
it wud be horizontal obviously
 
  • #7
nope! :wink:
 
  • #8
why...?
 
  • #9
suppose the water was ice, and the surface was at an angle, and a drop of water was on the surface …

what angle would the surface have to be for the drop of water to stay where it is? :wink:
 
  • #10
<=45 i guess
 
  • #11
phyeinstein_c said:
<=45 i guess

how do you get that? :confused:
 
  • #12
:P just guessing... mgsinθ is equal to the friction acting.. of surface tension watever... unless u describe the surface of ice to be smooth...
 
  • #13
phyeinstein_c said:
… unless u describe the surface of ice to be smooth...

yes, of course it's smooth! :rolleyes:
 
  • #14
ok... then it can't stay where it is..
 
  • #15
why not?

(if the block of ice is accelerating)
 
  • #16
oh yeah that's there... true.. then we can find the component of ma and normal reaction in horizontal direction and solve..
 

What are simple fluids?

Simple fluids are fluids that follow the Navier-Stokes equations, which describe the motion of fluids. These fluids do not have any complex properties like elasticity or viscosity, making them easier to study and analyze.

What is the application of simple fluids in science?

Simple fluids have many applications in science, including modeling the flow of air and water in weather patterns, understanding the behavior of fluids in pipes and channels, and studying the dynamics of fluids in space.

How are simple fluids different from complex fluids?

Simple fluids do not have any complex properties like elasticity or viscosity, which makes them easier to study and analyze. Complex fluids, on the other hand, have additional properties that make their behavior more difficult to predict and understand.

What are some real-life examples of simple fluids?

Some real-life examples of simple fluids include air, water, and oil. These fluids follow the Navier-Stokes equations and do not have any complex properties, making them ideal for studying fluid dynamics.

Why is it important to understand simple fluids?

Understanding simple fluids is important for various applications in science and engineering. It allows us to predict and control the behavior of fluids in different scenarios, from weather patterns to industrial processes, and helps us develop more efficient and effective technologies.

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