problem states that .... there is a u tube and filled with liquid of densities ρ and 2ρ. the base lenght of the tube is 'l'. now it is accelerated towards right with accl.=a. if the HEIGHT DIFFERENCE AFTER ACCELERATING THE SYSTEM IS '0'. then what was the height difference before acceleration??
P=ρgh; F=ma ; F=(ρ.V)a ;
The Attempt at a Solution
i tried to find pressure at bottom most level at interface of the two liquids, then the net force, then applied newtons 2nd law, but could'nt get the solution...