Simple harmonic motion of a body question

[srj200]

Homework Statement

A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation

A=Ai * sin(wt+ (pi/3)) ,

Where w = pi radians per second, t is in seconds, and Ai = 2.4m.
What is the phase of motion at t = 9.4 seconds? Answer in units of radians.

Homework Equations

A is the amplitude.
Ai is the initial amplitude.
w is actually "omega" but I didn't know how to enter that. That is the given angular velocity in rad/s.
Pi is 3.14...

The Attempt at a Solution

I honesty don't know where to start. I just plugged into the equation with the given data and got

-1.78355 meters.

The answer wants radians. Also, it asks for the "phase of motion". The answer I got is just the final amplitude at the given time.

Any help would be appreciated.
Thanks.

 

[nrqed]

Homework Statement

A body oscillates with simple harmonic motion along the x-axis. Its displacement varies with time according to the equation

A=Ai * sin(wt+ (pi/3)) ,

Where w = pi radians per second, t is in seconds, and Ai = 2.4m.
What is the phase of motion at t = 9.4 seconds? Answer in units of radians.

Homework Equations

A is the amplitude.
Ai is the initial amplitude.
w is actually "omega" but I didn't know how to enter that. That is the given angular velocity in rad/s.
Pi is 3.14...

The Attempt at a Solution

I honesty don't know where to start. I just plugged into the equation with the given data and got

-1.78355 meters.

The answer wants radians. Also, it asks for the "phase of motion". The answer I got is just the final amplitude at the given time.

Any help would be appreciated.
Thanks.

The phase is simply the argument of the sine function, namely the \omega t + \frac{\pi}{3} That's all there is to it.

 

[jamesrc]

I think the "phase of motion" is the argument of the sine function (=ωt+φ)

So at time t=0, the phase of motion would just be the phase constant (in your problem, π/3). And I think your answer should be between 0 and 2π, so if you compute something larger than 2π, you should subtract multiples of 2π until you are in that range.

E.T.A.: Looks like I was too slow...and Greek letters don't work the way they used to...

 

[Doc Al]

You can trace the SHM motion through 2\pi radians of "phase" as the body moves past the origin, goes to maximum + displacement, returns to the origin, goes to maximum - displacement, and then back where it started. When the body crosses the origin, consider its phase to be 0; when it reaches maximum amplitude, phase = \pi/2; back to the origin, phase = \pi. Etc.

Hint: Consider the argument of the sine function.

(Looks like nrqed and jamesrc both beat me to it!)

 

[srj200]

Thanks for the help. I got it.