Simple harmonic motion oscillate. What is the total energy

AI Thread Summary
The discussion focuses on calculating the total energy of a 50 g oscillating mass described by the equation x(t)=(2.0cm)cos(10t−π/4). The period T is determined to be approximately 0.6283 seconds, and the spring constant k is calculated as 5.000 N/m. The total energy is found using the formula 1/2kA^2, resulting in 0.001 J. An alternative method suggested involves calculating maximum kinetic energy from maximum velocity, which also yields the total energy. Both approaches are valid for determining the total energy in simple harmonic motion.
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Homework Statement


The position of a 50 g oscillating mass is given by x(t)=(2.0cm)cos(10t−π/4), where t is in s. If necessary, round your answers to three significant figures. Determine: The total energy.

Homework Equations


T = 2π/w
T = 2π√m/k
1/2kA^2
1/2mv^2
1/2kx^2

The Attempt at a Solution


T = 2π/10 = 0.6283s
k = 0.5kg / (0.6823/2π)^2 = 5.000N/m
1/2kA^2 = 0.5(5)(0.02)^2 = 0.001J
 
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Your answer is right.

In my opinion, it's more straightforward to find the answer from the maximum kinetic energy. Find the amplitude of dx/dt, which is the maximum velocity, which can be used to find the maximum kinetic energy (which equals the total energy because at that moment there's no potential energy).

But whichever way you like best is good.
 
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