 #1
 5
 0
I'm supposed to derive x as a function of time for a simple
harmonic oscillator (ie, a spring). According to my textbook
this is done by using newton's second law and hooke's law
as this: ma=kx and one gets a differential equation in
the second order. I can follow the calculations until this
happens: (see attached picture)
(where omega is the frequency)
I do get the equation (1) when I solve the differential
equation myself but I don't understand how equation (1) translates
to (2)????
I assume this must be done by using some trigonometric law?
if so then which one and how??
Thanks
harmonic oscillator (ie, a spring). According to my textbook
this is done by using newton's second law and hooke's law
as this: ma=kx and one gets a differential equation in
the second order. I can follow the calculations until this
happens: (see attached picture)
(where omega is the frequency)
I do get the equation (1) when I solve the differential
equation myself but I don't understand how equation (1) translates
to (2)????
I assume this must be done by using some trigonometric law?
if so then which one and how??
Thanks
Attachments

7.2 KB Views: 266