Simple harmonic motion question

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A mass of 10g suspended from a spring extends by 1cm, and after being pulled down an additional 0.5cm, the task is to calculate various parameters of its simple harmonic motion. The spring constant can be determined using the force equation mg = kx, where the force is 0.0981N. The period of motion can be calculated using T = 2π√(m/k). For maximum speed, the equation v = ω√(A² - x²) is appropriate, with x set to 0 at the equilibrium position. Understanding these calculations is crucial for solving the problem effectively.
no1schuifan
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Homework Statement


A mass of 10g is suspended from a spring of unstreched length 80cm. The extension produced is 1cm. The mass is pulled down a further 0.5cm and then released. Find:
a) the period of motion
b)the maximum speed of the mass
c) the max Ke of the mass
d)the tension in the spring when the mass is o.1cm below the equilibrium position
e) the max potential energy stored by the spring
f) the energy released by the spring when the mass moves from its lowest to the equilibrium position.

Any help of any sort will be greatly appreciated as I've only started studying this topic and finding it hard to understand. Many Thanks.
 
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no1schuifan said:

Homework Statement


A mass of 10g is suspended from a spring of unstreched length 80cm. The extension produced is 1cm. The mass is pulled down a further 0.5cm and then released. Find:
a) the period of motion
b)the maximum speed of the mass
c) the max Ke of the mass
d)the tension in the spring when the mass is o.1cm below the equilibrium position
e) the max potential energy stored by the spring
f) the energy released by the spring when the mass moves from its lowest to the equilibrium position.

Any help of any sort will be greatly appreciated as I've only started studying this topic and finding it hard to understand. Many Thanks.

Use the information given to find the spring constant (hint: spring force = mg when the mass is at equilibrium, which occurs when the extension is 1cm).
Then use the sping constant and the amplitude A= 0.5 cm to find all the answers.
 
How about you start by calculating the spring constant from the information that was given.

Hint: what is the force that causes the spring to extend?
 
thanks for you help.
So for the spring constant:
mg=w, 0.01*9.81= 0.0981 which i think is the force extending the spring?
if the spring constant = f/x is so then k = 9.81?
if that's the case then to calculate the period could i use T = 2pi ROOT(m/k)?
 
no1schuifan said:
thanks for you help.
So for the spring constant:
mg=w, 0.01*9.81= 0.0981 which i think is the force extending the spring?
if the spring constant = f/x is so then k = 9.81?
if that's the case then to calculate the period could i use T = 2pi ROOT(m/k)?

Looks good!
 
for part b am i correct in using this equation: v=wROOT(A^2-x^2) and if so because max speed is reached at the equilibirum position would i take x as 0?
 
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