Simple integration but i forgot how to do it

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The discussion revolves around a user's confusion regarding the integration of the function cos(πt). They initially made a sign error in their differentiation and struggled with the integration process. A participant clarified that the integration can be simplified by treating π as a constant and adjusting the differential accordingly. The user realized they were overcomplicating the problem and expressed gratitude for the assistance. The exchange highlights the importance of understanding basic integration techniques and the role of constants in calculus.
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Here is my work and problem:

i made an sign mistake, d/dt (cos t) = -sin(t).http://img101.imageshack.us/img101/561/blah4gk.jpg
 
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There's a problem with the link.

I get document not found
 
Ahh sorry!
http://img101.imageshack.us/img101/561/blah4gk.jpg
 
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That seems correct, what's the problem? You only forgot the unit vector j I believe.
 
oh sorry, i got that answer from someone, but didn't know how they got it! the parts i were i let u = cos (PI t);
du = -PIsin(PI t);
-1/PI de = sin(PI t);
but i don't know how that helps me when i plug it back in!
 
Just integrate each component. Pi is just a constant, you don't even need a real substitution for it. Do it indirectly by adjusting the dt and correcting in front of the integral.

\int {\cos \left( {\pi t} \right)dt} = \frac{1}<br /> {\pi }\int {\cos \left( {\pi t} \right)d\left( {\pi t} \right)} = \frac{{\sin \left( {\pi t} \right)}}<br /> {\pi } + C
 
OHh! i was making that way more complicated then it should havve been! thanks again TD! :D
 
No problem :smile:
 
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