Simple Math Question: Finding the Value of A in a Divisibility Problem

  • Thread starter Thread starter dnt
  • Start date Start date
AI Thread Summary
The discussion revolves around a math question from an SAT prep book asking for the value of A in the expression "2A" which is said to be divisible by both 3 and 6. Participants clarify that "2A" refers to a two-digit number where A is the unit digit, not the product of 2 and A. This means if A is 7, then "2A" represents the number 27. The confusion arises from the redundancy of stating divisibility by both 3 and 6, as any number divisible by 6 is inherently divisible by 3. Ultimately, the question is criticized for its poor wording, which could mislead test-takers.
dnt
Messages
238
Reaction score
0
i saw this in a SAT prep book and i cannot figure out what's going on here:

it says: "2A is divisible by both 3 and 6. If A is a digit, what is the value of A?"

seems simple enough but the choices are 1, 2, 3, 4, and 6. don't both 3 and 6 work?

if A is 3, then 2A is 6, and that is divisible by both 3 and 6.

if A is 6, then 2A is 12 and that is divisible by both 3 and 6.

what am i missing?
 
Physics news on Phys.org
Then mean "2A=2*10+A". (A is 4)
 
i don't understand. how did you get that equation and how did you even solve it?

2A=2*10+A?

wouldnt that mean A = 20? and i still have no ieda how you got that from the info i provided. please help.
 
dnt,

The question means "the digit 2 followed by some digit A," NOT 2*A.

- Warren
 
It's the SAT questions like these that kill me.
 
Any number divisible by 6 is divisible by 3, so it's somewhat superfulous to ask 'divisible by 3 and 6'.
 
dnt said:
i saw this in a SAT prep book and i cannot figure out what's going on here:

it says: "2A is divisible by both 3 and 6. If A is a digit, what is the value of A?"

seems simple enough but the choices are 1, 2, 3, 4, and 6. don't both 3 and 6 work?

if A is 3, then 2A is 6, and that is divisible by both 3 and 6.

if A is 6, then 2A is 12 and that is divisible by both 3 and 6.

what am i missing?

They meant "2A" as it is written down, not "two times A".

E.g. If "27" is "2A" then "A" is 7. Getit ?
 
AlphaNumeric said:
Any number divisible by 6 is divisible by 3, so it's somewhat superfulous to ask 'divisible by 3 and 6'.

Every number divisible by 6 is obviously divisible by 3, but not every number divisible by 3 is divisible by 6 (eg.27). That's why the syntax of the question is the way it is: 'divisible by 3 and 6' not 'divisible by 6 and 3'
 
Markjdb said:
That's why the syntax of the question is the way it is: 'divisible by 3 and 6' not 'divisible by 6 and 3'

That makes no sense at all, the order of the conditions has no bearing when "and" is the conjoiner. The question could simply have stated. "2A is divisible by six", and that would've had the same meaning without the redundancy.
 
  • #10
Indeed, I wonder how much time the person(s) who set the question thought about it :rolleyes: . Probably not aslong as we've been discussing it. :smile:
 
  • #11
thanks for the explanations - i do understand it now but i think its a poorly worded question, especially for anyone whos taken algebra (who is probably everyone if you are taking teh SAT).

2A means 2 times A (usually) when in math class.
 

Similar threads

Back
Top