Simple Moment of Inertia Question

AI Thread Summary
To increase the moment of inertia of a rod pivoted at one end by a factor of five, one approach is to attach four additional masses of equal size at a distance L from the pivot. The moment of inertia is calculated using the formula I = mr², where m is mass and r is the distance from the pivot. The discussion highlights that the original question lacks clarity regarding constraints such as the number of masses or their sizes. Alternative solutions could involve adding a single mass or varying the positions of the masses. The problem invites exploration of different methods to achieve the desired increase in moment of inertia.
tachu101
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Homework Statement


A rod of negligible mass is pivoted about one end. Masses can be attached to the rod at various positions along the rod. Currently, there is a mass (m) attached a distance (L) from the pivot. To increase the moment of inertia about the pivot by a factor of 5, you must attach...


Homework Equations



I=mr^2

The Attempt at a Solution



Io= mL^2
If= 5(Io) = mL^2(original mass)+4(mL^20) All I did was add four more masses of equal size at a distance L from the pivot. Is there another solution?
 
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You are correct. The definition of moment of Inertia is \sum_{i} m_{i} r^{2}_{i}
 
tachu101 said:
All I did was add four more masses of equal size at a distance L from the pivot. Is there another solution?
Sure, there are plenty of solutions. The question is a bit vague. Are there any constraints given? (Such as the the number of masses you are allowed to add or the size of the masses.)

For example: What if you could only add a single mass of equal size. How could you solve the problem then?
 
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