Simple Momentum Question: Calculating Y-Direction After Given Angles

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The discussion focuses on calculating the y-direction momentum components given specific angles and distances in a physics scenario. Participants are asked to use the momentum formula p=mv, with mass set at 1 unit and no specific units for calculations. The confusion arises around differentiating between distance and the y-component of momentum, particularly in relation to angles provided. One participant shares their calculations for two scenarios, but expresses uncertainty about the accuracy of their y-component calculations. Clarification is sought on the original question to better understand the problem.
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So, we were given a scenario and were asked to not calculate the momentum components in the x- directions. We were asked to use the simple formula of momentum(p) p=mv. Velocity was the root of the distance between the collisions and the mass was 1 unit. No specific units are to be used in these calculations. The question asks us to calculate momentum in the y-direction after being given specific angles. What's the difference between the distance and the y- component again?
 
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It'll be easier for someone to answer if you state the exact question you are trying to solve, along with the work you have done on it (i.e. what you have calculated)
 
1st scenario:
d=9.4cm
v= square root d= 3.1
I don't know how to calculate the y-components of momentum considering on an x-y plane, d is 34 degrees north of west. What I calculated was 9.4sin34 to get the y components but I can't shake the feeling that I might be wrong

2nd scenario, same as first but different numbers
d=14.7
v=3.83
d is 94 degrees east of north
y-component=14sin93
 
Could you state the whole question as given. It is quite confusing to me now.
 
don't worry, my prof explained and it now makes sense, thanks tho
 
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