Simple Pendulum Period Calculation for Different Conditions

AI Thread Summary
The discussion focuses on calculating the period of a pendulum under different conditions. Initially, the pendulum has a period of 1.8 seconds, and its length is then doubled, prompting a question about the new period. The relevant formula is T = 2π√(L/g), and participants clarify that the period will increase when the length is doubled. Additionally, the pendulum is considered on a planet with a gravitational acceleration of 16 m/s², raising further questions about how to apply the formula in this context. The conversation highlights confusion about variable notation and the implications of changing the pendulum's length and gravitational conditions.
mrnastytime
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Homework Statement


A pendulum has a period of 1.8 s.


Homework Equations


Its length is doubled. What is its period now?

The original pendulum is taken to a planet where g = 16 m/s2.
What is its period on that planet?



The Attempt at a Solution


T=2pi sqrt(L/g)
1.8=2pi sqrt(2L/g)



I don't what I am suppose to solve for. This looks like a very simple problem, but i can't seem to figure it out. Maybe I'm over thinking it.
 
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mrnastytime said:

Homework Statement


A pendulum has a period of 1.8 s.

Homework Equations


Its length is doubled. What is its period now?

The original pendulum is taken to a planet where g = 16 m/s2.
What is its period on that planet?

The Attempt at a Solution


T=2pi sqrt(L/g)
1.8=2pi sqrt(2L/g)

I don't what I am suppose to solve for. This looks like a very simple problem, but i can't seem to figure it out. Maybe I'm over thinking it.

Well your equations are almost right, but they asked what happens to T when you double L. Presumably 1.8 s is what it is when l = L and they want to know what T is when l = 2L.
 
What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?
 
mrnastytime said:
What is I?...if the length is doubled, shouldn't the time increase? but how would i interpret that on paper with the given equation?

Not I, little L.

The variable l, in the equation you wrote

T = 2π (g/l)1/2
 

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