- #1
JohanL
- 158
- 0
we have a particle in an infinite one-dimensional square well potential
[V(x)=0 for 0<x<L and V(x) is infinite otherwise]
and introduce a small potential (perturbation) in the middle of the
square well potential. Then the first order energy correction
for the ground state is 100 times lower than the first order correction
to the first excited state. I don't understand why...
The wave function without the small potential step in the middle
is zero in the middle for the first excited state and maximum in the middle
for the ground state. Has the diffrence in energy corrections something
to do with this?
[V(x)=0 for 0<x<L and V(x) is infinite otherwise]
and introduce a small potential (perturbation) in the middle of the
square well potential. Then the first order energy correction
for the ground state is 100 times lower than the first order correction
to the first excited state. I don't understand why...
The wave function without the small potential step in the middle
is zero in the middle for the first excited state and maximum in the middle
for the ground state. Has the diffrence in energy corrections something
to do with this?