Simple Physics Help: Understanding Force in Motion | Refresh Your Memory

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To lift a weight at a constant speed of 2m/s, the initial force must overcome both the gravitational force and provide the necessary acceleration. Once the weight reaches the desired velocity, the force required to maintain that speed equals the gravitational force acting on the object. At this point, no additional acceleration is needed, and the net force becomes zero, allowing the object to move upward at a constant velocity due to inertia. Understanding this principle simplifies the calculations involved in lifting objects with a pulley system. This clarification resolves the initial confusion regarding force requirements during different phases of motion.
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need some help to refresh my memory.

was just doing some specification checking... when the motor is to lift a weight...

let say the weight is to be move at 2m/s with 2sec when it start... and stay at 2m/s throughout after that...

the initial force would be F = ma + (Watever force it need to overcome)
where ma = m (dv/dt) ... simple

ok now the question... after it have reach the 2m/s velocity should the force F be
F = (watever force it need to overcome) only ?... coz i don't need any more acceleration and just constant speed
 
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Well, yes let's assume you want to lift an object with just a pulley. The initial lifting of the object as you stated would need more than the objects gravitational force. Then to have the object lift at a constant velocity the force would just need to be equivalent to the gravitational force upward. The mass would then have no acceleration/net force and thanks to the laws of inertia would be able to continue traveling upward at a constant velocity.
 
thanks... u safe me lots of trouble
 

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