Simple Physics Problem - Acceleration Formula

AI Thread Summary
To solve the physics problem of a cart rolling down a 5-meter incline for 6 seconds with an initial speed of 2 meters per second, the acceleration can be calculated using the formula a = (v1 - v2) / t. The final velocity is needed to determine acceleration, which requires understanding the relationship between distance, time, and acceleration. The formula x = x_0 + v_0 t + (1/2) a t^2 can be used, where x is the final position, x_0 is the initial position, v_0 is the initial velocity, t is time, and a is acceleration. Clarification on how to apply these variables is essential for finding the final velocity and subsequently the acceleration. Understanding these concepts is crucial for solving similar physics problems.
Dumblydore
Messages
2
Reaction score
0
1. A cart is rolling down an incline for 6 seconds. If the cart has a begginning speed of 2 meters per second and the incline is 5 meters long, what is the carts acceleration?



2. a= v1 - v2 / t



3. I'm just learning the acceleration formula in my physics class. I left my science book at school, thinking I would not need it because the worksheet we were given looked simple. But teacher threw in this problem and I'm not sure what to do about the incline. I need my final velocity to figure out the problem, but I'm sure what I do with the 5 meter long incline to get the final velocity.
 
Physics news on Phys.org
try to use x = x_0 + v_0 t + (1/2) a t^2
 
I'm not sure what all the variables in that formula are. I just need someone to explain how to get the final velocity.
 
x is final position, x_0 is initial position, v_0 is initial velocity, t is time, a = acceleration.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top