Simple proof question (limits)

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SUMMARY

The discussion centers on a proof in calculus regarding limits. The user attempts to prove that if the limit as x approaches c of f(x) exists, but the limit of [f(x) + g(x)] does not exist, then the limit of g(x) must also not exist. The proof employs a contradiction method, demonstrating that assuming the limit of g(x) exists leads to a logical inconsistency. The conclusion is that the user successfully constructed a valid proof by contradiction.

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  • Practice writing proofs in calculus, especially using proof by contradiction.
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htaMandPhysics
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I was reviewing some of the material in my calculus textbook when I realized that I really struggle with writing proofs. Therefore, I decided to attempt one of the easier proof related exercises found in the book. I would ask my teacher for help, but I am off for summer break.

Homework Statement


Prove that if the limit x->c of f(x) exists and limit x->c of [f(x)+g(x)] does not exist, then limit x->c of g(x) does not exist


Homework Equations




The Attempt at a Solution


Based on the properties of limits, if limit x→c of f(x)=L and limit x→c of g(x)=K, then the limit x→c of [f(x)+g(x)]=L+K. So let us assume that the limit x→c of g(x) does exist and is equal to K, and the limit x→c f(x) is equal to L. If that is so, then limit x→c of [f(x)+g(x)] must exist and is equal to L+K. However this creates a contradiction, as it was stated that limit x→c of [f(x)+g(x)] does not exist and therefore ≠ L+K. Therefore lim x→c of g(x) can't exist, else a contradiction is created.

So I tried to do a "proof by contradiction"... was I successful? If not, where exactly did I go wrong? Thanks



 
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