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Simple Q: Percent Disagreement

  1. Oct 7, 2006 #1
    Ok, I'm doing my Physics lab and I was told to give a "percent disagreement" if any.. I know it's a very simple question, but I want to make sure if I understood it right...

    So say I get an expected value to be .541 and when I calculated it, the answer is .715... so is the "percent disagreement" to be 32%? (.541 + .715/.541)

    Can someone verify if this is correct... thanks in advance :smile:
     
  2. jcsd
  3. Oct 7, 2006 #2

    arildno

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    Eeh?
    Whatever have you written here??
    You are to compute the relative error!
    (finding the percent from that is easy, just shift the decinal point two places in the correct direction)
     
  4. Oct 7, 2006 #3
    Whoops, I got the correct answer but I meant .541 - .715/.541
    and my true value was actually .541
    Anyway, I got it, thanks
     
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