quasar987 Science Advisor Homework Helper Gold Member Messages 4,796 Reaction score 32 Thread starter Nov 25, 2007 #1 If N is of null Lebesgue measure. Can we find a Borel set B of null measure such that N is entirely contained in B?
If N is of null Lebesgue measure. Can we find a Borel set B of null measure such that N is entirely contained in B?
morphism Science Advisor Homework Helper Messages 2,014 Reaction score 4 Nov 25, 2007 #2 The empty set!
quasar987 Science Advisor Homework Helper Gold Member Messages 4,796 Reaction score 32 Nov 25, 2007 #3 it's the other way around. we want B borel such that N is contained in B
quasar987 Science Advisor Homework Helper Gold Member Messages 4,796 Reaction score 32 Nov 27, 2007 #4 bump!
morphism Science Advisor Homework Helper Messages 2,014 Reaction score 4 Nov 27, 2007 #5 quasar987 said: it's the other way around. we want B borel such that N is contained in B Oops! This is also true. It follows from the fact that the Lebesgue measure is regular.
quasar987 said: it's the other way around. we want B borel such that N is contained in B Oops! This is also true. It follows from the fact that the Lebesgue measure is regular.